//* Fromula Evaluation, Integer vs. Floating Point *
#include <stdio.h>

int main()
{
    int     ia=2,   ib=3,   ic=4,   i;
    double  da=2.0, db=3.0, dc=4.0, d;

    printf("integer numbers: \n");
    i = ia+ib*ic;   printf("%d\n", i);
    i = ia+(ib*ic); printf("%d\n", i);
    i = (ia+ib)*ic; printf("%d\n", i);
    i = ia/ib;      printf("%d\n", i); // surprise
    d = ia/ib;      printf("%lf\n", d); // ok, store in double and check again

    printf("floating point numbers:\n");
    d = da+db*dc;   printf("%lf\n", d);
    d = da+(db*dc); printf("%lf\n", d);
    d = (da+db)*dc; printf("%lf\n", d);
    d = da/db;      printf("%lf\n", d);

    printf("\"new\" features:\n");
    i = 12 % 5;     printf("%d\n", i); // new operation, it is not calculator %
    i = ic % ib;    printf("%d\n", i);
//  d = dc % db;    printf("%d\n", i); // % works only with positive integers

    printf("integer vs. floating point operation:\n");
    d = ia/ib;      printf("%lf\n", d);
    d = da/db;      printf("%lf\n", d);
    d = ia/db;      printf("%lf\n", d);
    d = da/ib;      printf("%lf\n", d);

    printf("integer vs. floating point operation:\n");
    d = ia*ib/ic;   printf("%lf\n", d);
    d = (ia*ib)/ic; printf("%lf\n", d);
    d = ia*(ib/ic); printf("%lf\n", d);
    d = da*ib/ic;   printf("%lf\n", d);
    d = da*(ib/ic); printf("%lf\n", d);
    
    printf("type conversion:\n");
    d = ((double)ia)*ib/ic; printf("%lf\n", d);
    d = (double)ia*ib/ic;   printf("%lf\n", d); // it apples to next variable only, () not required here

    i = ia/db;          printf("%d\n", i);  // generates compiler warning
        // warning - compiler suspects an error but technically we could have 
        //           done it on purpose and it is possible to trnaslate this 
        //           suspicious notation, better avoid this kind of notation
    i = (int)(ia/db);   printf("%d\n", i);  
        // ... we tell the compiler that we really meant to do it so that there is no warning

   return 0;
}