//* data parsing and converting into numbers using atoi/atof - pointer notation *
#include <iostream>
#include <cstring>
#include <cstdlib>
using namespace std;

/*  
    Input: assume that the incoming data has the following format:
        +OK int_number1 double_number2
    or
        -ERR error message text
    Goal: if no error then read the two numbers into two variables
*/

void extract(const char* data, int &n1, double &n2, bool &ok);

int main() {
    char buffer[80];
    cin.getline(buffer,80);

    int     val1;
    double  val2;
    bool    extracted;

    extract(buffer, val1, val2, extracted);

    if (extracted) {
        cout << "RECEIVED DATA: " << val1 << " " << val2 << endl;
    }

    return(0);
}

void extract(const char* data, int &num1, double &num2, bool &ok) {
    ok=false;
    if (data[0]=='+') {
        // dillema: can we just check for '+' and '-' and assume that it is +OK or -ERR?
        // answer:  it depends on what is the source of ouf data (human or other program)
        //          and on how robust, fast, and big our program needs to be.

        const char* pointer = data;                         // start at the beginning of the array
        while (*pointer!=0 && *pointer!=' ') pointer++;     // move until either end of string or while space
        while (*pointer!=0 && *pointer==' ') pointer++;     // move until either end of string or white space ended
        if(*pointer!=0) {
            num1=atoi(pointer);
            while (*pointer!=0 && *pointer!=' ') pointer++;     // move until either end of string or while space
            while (*pointer!=0 && *pointer==' ') pointer++;     // move until either end of string or white space ended
            if(*pointer!=0) {
                num2=atof(pointer);
                ok=true;
            }
        }
    } else if (data[0]=='-') {
    } else {
        cout << "WARNING: data not in expected format!" << endl;
    }
}